Instructors Solution Manual

Instructors Solution Manual

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JjJJ (0.0003x2 - 0.2x + 50) dx = [0.000lx3 - 0.lx2 + 50x]fAsAs = [0.0001 (400)3 - 0.1 ( 400)2 + 50 . 400]- [0.0001(l00)3 - 0.l(l00)2 + 50 . 100] = $6300 26. Ca#39;(x) = 0.0003 x2 - 0.2x + 50 C(x) = /240Ad0Ad(0.0003x2 - 0.2x + 50) dx r t-3 Jl , 400 = 0.0003 .


Title:Instructors Solution Manual
Author:Marvin L. Bittinger
Publisher: - 2002-01-01
ISBN-13:

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